Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m/s. (a) By how much is the phase changed at a given point in 2.5 ms? (b) What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?

A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350 m/s.
(a) By how much is the phase changed at a given point in 2.5 ms?
(b) What is the phase difference at a given instant between two points separated by a distance of 10.0
cm along the direction of propagation?

Grade:12

1 Answers

Arun
25763 Points
3 years ago
a) Here given n = 100, v = 350 m/s ⇒ λ = v/m = 350/100 = 3.5 In 2.5 ms, the distance travelled by the particle is given by ∆* = 350 * 2.5 * 10^-3 So, phase difference ∅ = 2π/λ * ∆* ⇒ 2π/(350/100) * 350 * 2.5 * 10^-3 = (π/2). b) In the second case, Given ∆η = 10 cm = 10^-1 m. So, ϕ = 2π/*∆* = 2π * 10^-1/(350/100) = 2π/35

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free