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`        Two coherent point sources S1 and S2 vibrating in phase emit light of wavelength λ. The separation between the sources is 2λ. Consider a line passing through S2 and perpendicular to the line S1S2 . What is the smallest distance from S2  where a minimum of intensity occurs?`
10 years ago

```							Dear Sundeep,
See the diagram given below: Now we know that if I1and I2 are the intensities of the given two coherent sources of light.
then
resultant I = I1 + I2 + 2 √(I1I2) cos δ
δ = phase difference between the two waves coming from the two sources
tan δ = 2λ/y....................1
and also
cos δ = x/2λ.........................2
where x is the path difference between the waves and y is the distance along S2 at which  I is minimum
So phase difference must be odd multiples of π
so δ = (2m+1) π
and δ = x * 2π/ λ
From 2 and above equation we get cos θ = (2m+1)/4  where θ  is shown in the figure
for first minima
m=0
so cos θ = 1/4
tan θ = √15
and from 1
y = 2λ/√15
is the distance at which we get first minima
```
10 years ago
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