#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Two coherent point sources S1 and S2 vibrating in phase emit light of wavelength λ. The separation between the sources is 2λ. Consider a line passing through S2 and perpendicular to the line S1S2 . What is the smallest distance from S2  where a minimum of intensity occurs?

## 1 Answers

11 years ago

Dear Sundeep,

See the diagram given below: Now we know that if I1and I2 are the intensities of the given two coherent sources of light.

then

resultant I = I1 + I2 + 2 √(I1I2) cos δ

δ = phase difference between the two waves coming from the two sources

tan δ = 2λ/y....................1

and also

cos δ = x/2λ.........................2

where x is the path difference between the waves and y is the distance along S2 at which  I is minimum

So phase difference must be odd multiples of π

so δ = (2m+1) π

and δ = x * 2π/ λ

From 2 and above equation we get cos θ = (2m+1)/4  where θ  is shown in the figure

for first minima

m=0

so cos θ = 1/4

tan θ = √15

and from 1

y = 2λ/√15

is the distance at which we get first minima

## ASK QUESTION

Get your questions answered by the expert for free