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i have a doubt
what is the formulae to find dark fringe
is it (2n+1)LD/2d
or it is (2n-1)LD/2d
where L is lambda
both are correct but 2n-1 is preferably used
in the formula 2n-1 n is the position of dark fringe
while for 2n+1 position of fringe is n+1
example n=0 => 2X(0) +1 =1 [1ST DARK FRINGE]
thnk u
Dear Vijesh
Both the formulae are correct, on putting n as sum integer we get two successive dark fringes by those 2 formulae
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