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a short linear object of length L lies on the axis of a spherical mirror of focal length f at a distance u from the mirror. what will be the axial length of the image ???
center of object is u distance apart from mirror... now , one end is at u1= u-L/2 & other end is at u2 = u+L/2 1/v + 1/u = 1/f (mirror formula) v = fu/u-f .................1 image for one end = v1 = fu1/u1-f image for other end = v2 = fu2/u2-1 v1-v2 = length of image = f2(u2-u1)/(u1-f)(u2-f) now solve this & get the ans
center of object is u distance apart from mirror...
now , one end is at u1= u-L/2 &
other end is at u2 = u+L/2
1/v + 1/u = 1/f (mirror formula)
v = fu/u-f .................1
image for one end = v1 = fu1/u1-f
image for other end = v2 = fu2/u2-1
v1-v2 = length of image = f2(u2-u1)/(u1-f)(u2-f)
now solve this & get the ans
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