# The length of simple pendulum is made equal to the radius of the earth .Its period of oscillation will be?

Arun
25758 Points
5 years ago
Time period of simple pendulum of large length(l) is given by,

T = 2*(pi)* $\LARGE \sqrt$1/((1/l) + (1/R))g
When l = R
Hence
T = 2*(pi) *$\LARGE \sqrt$R/2g