The frequency of note emitted by source changes by 20%as it approaches observer.As it recedes away from him,the apparent frequency will be?

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Arun · Answer

Dear Prema n(120/100) = (v / v – vs) *n 1.2 V – 1.2 Vs = V 0.2 V = 1.2 Vs Vs = V/6 when it recedes away (100 – x / 100) * n = (V / V + Vs)*n 1 – x /100 = 6/7 x = 14.3 % hence 14.3% different from actual frequency

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The frequency of note emitted by source changes by 20%as it approaches observer.As it recedes away from him,the apparent frequency will be?

The frequency of note emitted by source changes by 20%as it approaches observer.As it recedes away from him,the apparent frequency will be?

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The frequency of note emitted by source changes by 20%as it approaches observer.As it recedes away from him,the apparent frequency will be?

The frequency of note emitted by source changes by 20%as it approaches observer.As it recedes away from him,the apparent frequency will be?

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