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Good evening sir...
Beats application sir.
Explain it.

Ramu Ramu , 7 Years ago
Grade
anser 1 Answers
Eshan

Last Activity: 7 Years ago

Dear student,

The difference in frrequencies of tuning forks A and B is 5Hz. When B is loaded with wax, its frequency decreases and the new frequency again differs from A by 5 Hz. Hence intially the frequency of B must have been 5 Hz higher than that of A and later it must have been 5 Hz lower than it. Hence frequency of A is 512Hz-5Hz=507Hz.

Hope it helps. Regards.
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