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Good evening sir...Beats application sir.Explain it.
Dear student,The difference in frrequencies of tuning forks A and B is 5Hz. When B is loaded with wax, its frequency decreases and the new frequency again differs from A by 5 Hz. Hence intially the frequency of B must have been 5 Hz higher than that of A and later it must have been 5 Hz lower than it. Hence frequency of A is 512Hz-5Hz=507Hz.Hope it helps. Regards.
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