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Good evening sir... Beats application sir. Explain it.

Good evening sir...
Beats application sir.
Explain it.

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1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

The difference in frrequencies of tuning forks A and B is 5Hz. When B is loaded with wax, its frequency decreases and the new frequency again differs from A by 5 Hz. Hence intially the frequency of B must have been 5 Hz higher than that of A and later it must have been 5 Hz lower than it. Hence frequency of A is 512Hz-5Hz=507Hz.

Hope it helps. Regards.

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