Good afternoon sir . VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000. Here Sigma= liquid density=? Ro=mass density=? How to get those values. Please explain sir.

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Venkat · Answer

It is given in the question as 5/9 . so, V = 1500 sqrt(g(1-5/9)/g) = 1500sqrt (4/9) = 1500 x 2/3 = 1,000 m/s

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Good afternoon sir . VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000. Here Sigma= liquid density=? Ro=mass density=? How to get those values. Please explain sir.

Good afternoon sir .
VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000.
Here
Sigma= liquid density=?
Ro=mass density=?
How to get those values.
Please explain sir.

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Good afternoon sir . VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000. Here Sigma= liquid density=? Ro=mass density=? How to get those values. Please explain sir.

Good afternoon sir . VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000.HereSigma= liquid density=?Ro=mass density=?How to get those values.Please explain sir.

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Good afternoon sir .
VB = 1500 √{g[1-(sigma/Ro)]/g} = 1000.
Here
Sigma= liquid density=?
Ro=mass density=?
How to get those values.
Please explain sir.