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A string is stretched so that its length is increased by 1/x of its original length.The ratio of fundamental frquency of transverse vibration to that of fundamental frequency of longitude vibration will be:-

RITWIKA ghosh , 7 Years ago
Grade 12th pass
anser 1 Answers
Norman Manchu

Last Activity: 7 Years ago

When you stretch a string a restoring force acts over it which equals F=-kx where the negative sign indicates opposite direction
 
Keeping this in mind-
\frac{n1}{n2}=\frac{v1}{\lambda1}\frac{\lambda2}{v2}
v=√T|√m
And wavelength for a stretched string=2xL
L1=L and L2=L|n
 
T1=kx=kL and T2=kx=kL|n
Substitute the values (its hectic on keyboard)to get answer which will be 1:√\eta!
 

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