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# A string is stretched so that its length is increased by 1/x of its original length.The ratio of fundamental frquency of transverse vibration to that of fundamental frequency of longitude vibration will be:-

Norman Manchu
151 Points
3 years ago
When you stretch a string a restoring force acts over it which equals F=-kx where the negative sign indicates opposite direction

Keeping this in mind-
$\frac{n1}{n2}=\frac{v1}{\lambda1}\frac{\lambda2}{v2}$
v=√T|√m
And wavelength for a stretched string=2xL
L1=L and L2=L|n

T1=kx=kL and T2=kx=kL|n
Substitute the values (its hectic on keyboard)to get answer which will be 1:√$\eta$!