A shot leaves a gun at the rate of 160m/s calculate the greatest distance to which it could be projected? G=10m/s

To calculate the greatest distance a projectile can travel, we use the formula for maximum range:

R = (u² sin(2θ)) / g

Where:

R = Range (maximum distance)
u = Initial velocity (160 m/s)
θ = Angle of projection (for maximum range, θ = 45°)
g = Acceleration due to gravity (10 m/s²)
Step 1: Substitute known values into the formula.

Since sin(2θ) is maximum at θ = 45°, sin(90°) = 1.

R = (160² × sin(90°)) / 10
R = (160² × 1) / 10
R = 25600 / 10
R = 2560 m

Final Answer: The greatest distance to which the shot could be projected is 2560 meters.