Saurabh Koranglekar
Last Activity: 6 Years ago
To calculate the greatest distance a projectile can travel, we use the formula for maximum range:
R = (u² sin(2θ)) / g
Where:
R = Range (maximum distance)
u = Initial velocity (160 m/s)
θ = Angle of projection (for maximum range, θ = 45°)
g = Acceleration due to gravity (10 m/s²)
Step 1: Substitute known values into the formula.
Since sin(2θ) is maximum at θ = 45°, sin(90°) = 1.
R = (160² × sin(90°)) / 10
R = (160² × 1) / 10
R = 25600 / 10
R = 2560 m
Final Answer: The greatest distance to which the shot could be projected is 2560 meters.
