Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

Grade:10

1 Answers

Jitender Pal
askIITians Faculty 365 Points
6 years ago
Sol. Time period, T = 4 * 5 ms = 20 * 10–3 = 2 * 10–2 s λ = 2 * 2 cm = 4 cm frequency, f = 1/T = 1/(2 * 10–2) = 50 s–1 = 50 Hz Wave speed = λ f = 4 * 50 m/s = 2000 m/s = 2 m/s

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free