Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A loudspeaker produces a musical sound by the oscillation of a diaphragm. If the amplitude of oscillation is limited to 1.20 × 10 -3 mm, what frequencies will result in the acceleration of the diaphragm exceeding g?

A loudspeaker produces a musical sound by the oscillation of a diaphragm. If the amplitude of oscillation is limited to 1.20 × 10-3 mm, what frequencies will result in the acceleration of the diaphragm exceeding g?

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
6 years ago
Here the value of maximum acceleration ax of the diaphragm is equal to the acceleration due to gravity g and which has value 9.81 m/s2 on the surface of Earth.
To obtain the frequency of diaphragm, substitute 9.81 m/s2 for acceleration ax, 1.20×10-3 mm for the amplitude of oscillation in the equation f = (√ ax/ xm) /2π,
f = (√ ax/ xm) /2π
= (√(9.81 m/s2 /1.20×10-3 mm) (1 mm/10-3 m )) /2×3.14
=455/s
= (455/s) (1 Hz/(1/sec))
= 455 Hz
From the above observation we conclude that the frequency of diaphragm would be 455 Hz.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free