A body executing SHM along a straight line has a velocity of 3 m/s when it is at a distance sof 4m from the mean position and 4 m/s when at a distance of 3m from the mean position, find its angular frequency and amplitude.

Using V= Wsqrt(A^2 - X^2) Put V= 4,X=3 (get equation 1) V=3, X= 4 (get equation 2)Solve 2 equation in 2 variables get A= 5, W=1.

V=w√[a^2-x^2]. A simple harmonic motion when the acceleration is directly proportional to displacement in negative direction and a=-w^2y

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Yash Chourasiya