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Grade 12th passWave Motion

A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy of the system is 2.00 J. Find (a) the force constant of the spring and (b) the amplitude of the motion.

Profile image of Mehboob Elahi
7 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
a) T = 2pi / w so w = 2 pi / T

w = sqrt ( k / m )

so k = w²* m 

b) (1/2)* k * xmax ² = 2,00 J

so, xmax = sqrt( 2,00 * 2 / k)
 
hopebit helps
 
Regards
Arun (askIITians forum expert)

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