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Suppose there is a pulley with a mass m hanging in one one side of the string and the other side is attached to a vibrator by keeping the string in a horizontal position.The linear mass density of the string is 0.002 kg/m.The length of the spring between the pulley and the vibrator. is L=2.00 m.When the mass is either 16kg or 25 kg, standing waves are observed; however no standing waves are observed with any mass between these values.Assume the pulley to be frictionless.
What is the frequency of the vibrator?
What is the largest mass for which standing waves could be observed?

Anirban Mukherjee , 13 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to analyze the conditions under which standing waves form on the string connected to the vibrator and the mass hanging from the pulley. The key concepts involved here are wave mechanics and the relationship between tension, mass, and frequency in a vibrating string.

Understanding the System

In this setup, we have a string with a linear mass density (μ) of 0.002 kg/m, a length (L) of 2.00 m, and a mass (m) hanging on one side. The tension (T) in the string is created by the weight of the hanging mass, which is given by the formula:

T = m * g

where g is the acceleration due to gravity (approximately 9.81 m/s²). The tension in the string affects the speed of the waves traveling along it, which can be calculated using the formula:

v = √(T/μ)

where v is the wave speed. The frequency (f) of the standing waves is related to the wave speed and the wavelength (λ) by:

f = v / λ

Finding the Frequency of the Vibrator

Standing waves occur when the length of the string supports a whole number of wavelengths. For a string fixed at both ends, the wavelengths of the standing waves can be expressed as:

λ_n = 2L/n

where n is the mode number (1, 2, 3, ...). The corresponding frequencies for these modes can be expressed as:

f_n = n * (v / 2L)

To find the frequency of the vibrator, we need to determine the tension for both masses (16 kg and 25 kg) and calculate the wave speed for each case.

Calculating Tension and Wave Speed

  • For m = 16 kg:
  • T = 16 kg * 9.81 m/s² = 156.96 N

    v = √(156.96 N / 0.002 kg/m) = √78480 m²/s² ≈ 280.5 m/s

    Now, we can find the frequency for the fundamental mode (n=1):

    f_1 = 1 * (280.5 m/s / (2 * 2.00 m)) = 70.125 Hz

  • For m = 25 kg:
  • T = 25 kg * 9.81 m/s² = 245.25 N

    v = √(245.25 N / 0.002 kg/m) = √122625 m²/s² ≈ 349.5 m/s

    For the fundamental mode:

    f_1 = 1 * (349.5 m/s / (2 * 2.00 m)) = 87.375 Hz

Determining the Largest Mass for Standing Waves

Standing waves are observed only for specific masses (16 kg and 25 kg) and not for any mass in between. This implies that the system has specific resonant frequencies that correspond to these masses. The largest mass for which standing waves can be observed is therefore 25 kg, as it produces the highest tension and thus the highest frequency of standing waves.

Summary of Findings

The frequency of the vibrator can be calculated as follows:

  • For 16 kg: 70.125 Hz
  • For 25 kg: 87.375 Hz

The largest mass for which standing waves could be observed is 25 kg. This analysis illustrates how tension in the string, determined by the hanging mass, directly influences the frequency of the standing waves produced in the system.

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