An engine whestles at a frequency of 256Hz moves towards a wall with a velocity of 50m/s. How many number of beats will be sounded to the engine?

ravi pratap Grade: 12

        An engine whestles at a frequency of 256Hz moves towards  a wall with a velocity of 50m/s. How many number of beats will be sounded to the engine?

9 years ago

Answers : (1)

devashish trivedi

8 Points

										Doppler's fomula is
           n' = n (v -vo)/(v-vs)
where n' = apprant frequency
           n = original frequency
         v = spped of sound in air that is 330 m/s
      vo = speed of observer
     vs = speed of the source
Here n = 256 hz vo = 0 vs = 50m/s pluging in the values we will get n = 497 hz
now with this frequency the sond will reflect from the wall so the source will be stationary
we will again use the same formula
                                                       n" = n (v -vo)/(v-vs)
now vo = 50m/s , vs = 0 and v =330m/s n" = frequency heard by the observer
now pluging in the values we will have
                                                    n" = 497(330 - 50)/(330 - 0)
                                                           = 497x 280/330
                                                          = 422hz so the no of beats heard by the observer is n" - n = 422 - 256=      166 beats per second