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the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

ravi , 8 Years ago
Grade 12th pass
anser 1 Answers
Shashank Singh
since magnitude of the vector product is equal to the scalar product
so, ABsin<theta>= ABcos<theta>
we get that <theta>= pi/4
(A+B)^2= A^2+B^2+2ABcos<theta>
=A^2+B^2+ sqrt2AB...............[ANS]
Last Activity: 8 Years ago
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