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the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is
since magnitude of the vector product is equal to the scalar productso, ABsin<theta>= ABcos<theta>we get that <theta>= pi/4(A+B)^2= A^2+B^2+2ABcos<theta>=A^2+B^2+ sqrt2AB...............[ANS]
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