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the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

Grade:12th pass

1 Answers

Shashank Singh
askIITians Faculty 57 Points
3 years ago
since magnitude of the vector product is equal to the scalar product
so, ABsin<theta>= ABcos<theta>
we get that <theta>= pi/4
(A+B)^2= A^2+B^2+2ABcos<theta>
=A^2+B^2+ sqrt2AB...............[ANS]

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