the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

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Shashank Singh · Answer

since magnitude of the vector product is equal to the scalar product so, ABsin= ABcos we get that = pi/4 (A+B)^2= A^2+B^2+2ABcos =A^2+B^2+ sqrt2AB...............[ANS]

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the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

the magnetude of the vector product of two vectors A and B equal to the scaler product. The square of the sum of these vectors is

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