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Question 9 is the question I want to ask you. It is from the Fiitjee package of vectors and of exercise 3.

Question 9 is the question I want to ask you. It is from the Fiitjee package of vectors and of exercise 3.

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Grade:12

1 Answers

sahil
142 Points
3 years ago
sol: |A.B|=|abcos(¤)| and |A×B|=|absin(¤)| condition is |absin|=|abcos| or |sin|=|cos|where ¤ can tale value from 0 to 180degree.Now only 45 and 135 satisfy so option c is correct(since mod or psistive value is taken so 135 degree also satisfy)

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