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Vectors> Please please please please solveI have c...

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Please please please please solveI have complet answer

Pawan , 7 Years ago

Grade 12th pass

3 Answers

Piyush Kumar Behera

@Pawan

In the given question as $\vec{A}$ is a unit vector

hence the magnitude of $\vec{A}$ is 1

So as we know that magnitude of $\vec{A}$ is $\sqrt{3^{2}+2^{2}+b^{2}}$

So

=> $\sqrt{3^{2}+2^{2}+b^{2}} = 1$

=> ${3^{2}+2^{2}+b^{2} = 1$

$b=\sqrt{-12}$

As b will come as a square root of a negative term so it has no real values.

I hope it helps.

Regards

Piyush Kumar Behera

Approved

Last Activity: 7 Years ago

vedant

as the vector a is a unit vector its magnitude should be 1 therefore square root of 3 square plus 2 square plus b square should be 1 therefore b is root 12 iota where iota is root of minus 1

Last Activity: 7 Years ago

Khimraj

Unit vector is a vector whose magnitude is 1.

So |A| = 1

then $\sqrt{3^{2} + 2^{2} + b^{2}}$ = 1

So b = 12i.

Hope it clears.

Last Activity: 7 Years ago

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