if the vectors a=3i+j-2k,b=-i+3j+4k,c=4i-2j-6k costitiute sides of a triangle ABC then the length of median bisecting vector c is

Question

Vikas TU · Answer

Let CC1 be the median CC1 = |CC1| = |1/2 (CA + CB)| |1/2 (a-c+b-c)| = |1/2(a+b-2c)| |1/2(3i +j -2k-i+3j+4k-2(4i-2j-6k)| =|-3i+4j+7k| = sqrt(9+16+49) => sqrt(74) Hope this helps

Aditya Gupta · Answer

as usual, vikas’ answer is wrong. note that for any triangle ABC, AB + BC + CA= 0 where bold chars represent vectors. now, if here we let a= BC= 3i + j – 2k, b= AC = – CA= –i + 3j + 4k then c= 4i – 2j – 6k= BC+CA= – AB= BA so now median length bisecting c is= | b + ( c /2)| = |i + 2j + k| = sqrt(1+4+1) = sqrt(6) kindly approve :=)

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

if the vectors a=3i+j-2k,b=-i+3j+4k,c=4i-2j-6k costitiute sides of a triangle ABC then the length of median bisecting vector c is

if the vectors a=3i+j-2k,b=-i+3j+4k,c=4i-2j-6k costitiute sides of a triangle ABC then the length of median bisecting vector c is

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Vectors

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship