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`        If Cos x/Cos y=2 and Cos(x-y)=√3/2 then tan y is  how much.this qjequest is from trigonometry`
one year ago

```							cos(x-y)=sqrt3/2cos(pi/6)=sqrt3/2x-y = pi/6x=y+pi/6replace x by y+pi/6 in the other equation given.cos x/cos y =2cos (y+pi/6)=2*cos y(cos y)(cos pi/6)-(sin y)(sin pi/6) = 2*cos ydividing all by cos y get cos pi/6 - (tan y)*1/2 = 2sqrt 3/2 - (tan y) *1/2 = 2tan y = sqrt 3 -4
```
one year ago
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