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if a vector A= i+xj+3k is rotated through an angle and is double the magnitude resulting vector is B =4i+(4x-2)j+2k then what will be the value of x.

if a vector A= i+xj+3k  is rotated through an angle and is double the magnitude resulting vector is B =4i+(4x-2)j+2k then what will be the value of x.

Grade:12th pass

2 Answers

vishal kumar
20 Points
3 years ago
even if the vector is rotated the magnitude remains same.
so the new vector magnitude is 2(10+x2)1/2 since we are doubling the magnitude after rotation. now this is equal to magnitude of vector B so solving them we get value of x
Deepak Kumar Shringi
askIITians Faculty 4405 Points
3 years ago
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