# A plane flying horizontally at a height of 1500 m with the velocity of 200 m/s passes directly overhead an antiaircraft gun. Then the angle with the horizontal at which the gun should be fired for the shell with a muzzle velocity of 400m/s to hot the plane, is

Arun
25758 Points
4 years ago
if we make a simple figure of how it is projected. then,
assume after t sec the bullet strikes the plane.
so the distance covered by plane=horizontal distance covered by the bullet
200 t=(400 cos $\theta$)t
$\theta$=60 degrees with horizontal