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Dear cool gal
1) let a point on y axix (0,y,0)
now use distance formula
[(5-0)2 +(5-y)2 +(2-0)2]1/2 = [(3-0)2 +(1-y)2 +(2-0)2]1/2
or
[(5-0)2 +(5-y)2 +(2-0)2] = [(3-0)2 +(1-y)2 +(2-0)2]
25 + (5-y)2 =9+ (1-y)2
16 =(1-y)2 - (5-y)2
16 =(1-y-5+y)(1-y+5-y)
16 =-4(6-2y)
40 = 8y
y=5
so point is (0,5,0)
plese post different question in different post.
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