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The value of x for which the angle between the vectors a=xi-3j-k b=2xi+xj-k is acute and the angle between the vectors b and the axis of ordinate is obtuse are
Dear pallavi
angle between the vectors a=xi-3j-k b=2xi+xj-k is acute so cosΘ >0 or a.b>0 2x2 -3x +1>0
(x-1)(2x-1)>0
x<1/2 or x>1
angle between the vectors b and the axis of ordinate is obtuse
so b.j<0
x<0
fo final solution is x<0
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