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Trigonometric idetenties: prove that (Cos^2A/1-tanA)+(sin^3A/sinA-cosA)=1+sinacosa

Trigonometric idetenties: prove that (Cos^2A/1-tanA)+(sin^3A/sinA-cosA)=1+sinacosa

Grade:10

1 Answers

Arun
25750 Points
6 years ago
LHS
Cos²A/1- tanA  +  sin³A/sinA - cosA
Cos³A/(cosA - sinA)  + sin³A/(sinA- cosA)
(Sin³A - cos³A)/(sinA- cosA)
Open the formula of a3 - b³ = (a-b) (a²+b² +ab)
We are left with
= Sin²A + cos²A + sinA cosA
= 1 + sinA cosA

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