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Trigonometric idetenties: prove that (Cos^2A/1-tanA)+(sin^3A/sinA-cosA)=1+sinacosa
LHSCos²A/1- tanA + sin³A/sinA - cosACos³A/(cosA - sinA) + sin³A/(sinA- cosA)(Sin³A - cos³A)/(sinA- cosA)Open the formula of a3 - b³ = (a-b) (a²+b² +ab)We are left with= Sin²A + cos²A + sinA cosA= 1 + sinA cosA
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