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Grade: 12
        TanA+TanB+Tanc-sin(A+B+C)/cosAcosBcosC=? Please tell the answer
one year ago

Answers : (1)

Arun
23032 Points
							
Dear Bhoomika
 
tanA + tanB + tanC - [sin(A+B)*cosC + cos(A+B) *sinC]/cosA cosB cosC
= tanA + tanB + tan C -[sinA cosB cosC +cosAcosB cosC + cosAcosB sinC - sinA sinB sinC]/cosA cosB cosC
= tanA + tanB + tanC - tanA - tanB - tanC + tanA tanB tanC
= TanA tanB tanC
 
Regards
Arun (askIITians forum expert)
one year ago
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