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TanA+TanB+Tanc-sin(A+B+C)/cosAcosBcosC=? Please tell the answer
Dear Bhoomika tanA + tanB + tanC - [sin(A+B)*cosC + cos(A+B) *sinC]/cosA cosB cosC= tanA + tanB + tan C -[sinA cosB cosC +cosAcosB cosC + cosAcosB sinC - sinA sinB sinC]/cosA cosB cosC= tanA + tanB + tanC - tanA - tanB - tanC + tanA tanB tanC= TanA tanB tanC RegardsArun (askIITians forum expert)
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