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Grade 12th passTrigonometry

Sir/Madam
I want to find the value of Sin37 Trigonomtrically! Please help me!
With Regards!
Anish

Profile image of Anish Ranjan Bhattacharjee
9 Years agoGrade 12th pass
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1 Answer

Profile image of Umakant biswal
9 Years ago
in a right angled triangle with sides as 3,4,5 or 6,8,10 , the angles other than the right angles are 37 degre and 53 degree . 
so, 
sin 37 degree = 3/5 = cos 53 degree 
sin 53 degree = 4/5 = cos 37 degree 
the value will come around 0.60181574 , 
else , u can do it by taylor series , but understanding it will be complicated . 
so, better follow this method , 
ALL THE BEST ..