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sinx. (sinx + cosx) = ksin2x+sinx cosx=k1/2- cos2x/2 +sin2x/2 =ksin2x -cos2x=2k-1 for real solution-√2 ≤2k-1 ≤ √2 (1-√2)/2 ≤k ≤ (1+ √2)/2In this solution , i don`t get why -√2 and √2 comes ? Please explain

sinx. (sinx + cosx) = ksin2x+sinx cosx=k1/2- cos2x/2 +sin2x/2 =ksin2x -cos2x=2k-1 for real solution-√2 ≤2k-1 ≤ √2 (1-√2)/2 ≤k ≤ (1+ √2)/2In this solution , i don`t get why -√2 and √2 comes ? Please explain

Grade:12

1 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
Dear student

Please upload the question as it is , it is difficult to analyse question this way

Regards

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