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Grade: 12th pass 

                        
sinx. Cosx. Cos2x​= K has a solution, if K belong to the interval ​
3 years ago

Answers : (1)

sonika p
129 Points 
							
sinx.cox.cos2x = k
Multiplying by 2 on both sides, 
2*sinx.cox.cos2x =2* k
sin2x.cos2x = 2k
Multiplying by 2 on both sides,
2*sin2x.cos2x = 2*2k
sin4x = 4k
interval of sin4x, -1
therefore, -1
-1/4 
interval of k is [-0.25,0.25]
3 years ago
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