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sinx. Cosx. Cos2x= K has a solution, if K belong to the interval sinx. Cosx. Cos2x= K has a solution, if K belong to the interval
sinx.cox.cos2x = kMultiplying by 2 on both sides, 2*sinx.cox.cos2x =2* ksin2x.cos2x = 2kMultiplying by 2 on both sides,2*sin2x.cos2x = 2*2ksin4x = 4kinterval of sin4x, -1therefore, -1-1/4 interval of k is [-0.25,0.25]
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