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sin10.sin30.sin50.sin70.sin90=?
what should be the answer for this difficult question please tellme

Amit , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
As sin 90 = 1
We have sinx*sin(60 – x)*sin(60 + x) = 1/4* sin3x
sin10*sin30*sin50*sin70
=1/2*sin10*sin(60 – 10)*sin(60 + 10)
=1/2*1/4*sin(3*10)
=1/2*1/4*1/2
=1/16

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