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Grade: 12
        
sin10.sin30.sin50.sin70.sin90=?
what should be the answer for this difficult question please tellme
6 months ago

Answers : (1)

Arun
21013 Points
							
Dear student
 
As sin 90 = 1
We have sinx*sin(60 – x)*sin(60 + x) = 1/4* sin3x
sin10*sin30*sin50*sin70
=1/2*sin10*sin(60 – 10)*sin(60 + 10)
=1/2*1/4*sin(3*10)
=1/2*1/4*1/2
=1/16
6 months ago
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