nooglerApproved Tutor Answer11 Years agocos(tan-1(sin(cot-1x)))=cos(tan-1(sin(sin-1(1/root of 1+x2)))) cot-1x=tan-1(1/x)=sin-1(1/1+x2)1/2 =cos(tan-1(1/1+x2)1/2) sin(sin-1x)=x =cos(cos-1(1+x2/2+x2)1/2) tan-1(1/1+x2)=cos-1(1+x2/2+x2)1/2 =(1+x2/2+x2)1/2
noogler11 Years agocos(tan-1(sin(cot-1x)))=cos(tan-1(sin(sin-1(1/root of 1+x2)))) =cos(tan-1(1/1+x2)1/2) =cos(cos-1(1+x2/2+x2)1/2) =(1+x2/2+x2)½ cot-1x=tan-1(1/x)=sin-1(1/1+x2)1/2 sin(sin-1x)=xtan-1(1/1+x2)=cos-1(1+x2/2+x2)1/2