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`        PT costan-1 sincot-1x= root of x2+1/x2+2`
5 years ago

```							cos(tan-1(sin(cot-1x)))=cos(tan-1(sin(sin-1(1/root of 1+x2))))                      cot-1x=tan-1(1/x)=sin-1(1/1+x2)1/2                                =cos(tan-1(1/1+x2)1/2)                                            sin(sin-1x)=x                               =cos(cos-1(1+x2/2+x2)1/2)                                        tan-1(1/1+x2)=cos-1(1+x2/2+x2)1/2                               =(1+x2/2+x2)1/2
```
5 years ago
```							cos(tan-1(sin(cot-1x)))=cos(tan-1(sin(sin-1(1/root of 1+x2))))                                   =cos(tan-1(1/1+x2)1/2)                                     =cos(cos-1(1+x2/2+x2)1/2)                                   =(1+x2/2+x2)½  cot-1x=tan-1(1/x)=sin-1(1/1+x2)1/2 sin(sin-1x)=xtan-1(1/1+x2)=cos-1(1+x2/2+x2)1/2
```
5 years ago
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