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My question is (r1+r2) (r2+r3) (r1+r3) divided by Rs^2

My question is
(r1+r2) (r2+r3) (r1+r3) divided by Rs^2
 

Grade:11

2 Answers

Arun
25750 Points
4 years ago
Dear student
 
Yes it is divisible.
I have attached the solution of this question as an image. Please check and let me know if any difficulty happen.
576-816_1566791142196170568199.jpg
Aditya Gupta
2081 Points
4 years ago
dear aditi, aruns answer is totally crap and you shall get zero marks for such a solution. he has simply taken a special case of equilateral triangle. but we need to prove for general triangle.
we know the standard formulas:
r1= A/(s – a), r2= A/(s – b), r3= A/(s – c) where A is area of triangle and s is semiperimeter, 2s= a+b+c
R= abc/4A
also, by heron formula
A^2= s(s – a)(s – b)(s – c)
substitute these values and simplify, we get
A^3*abc/R(s(s – a)(s – b)(s – c))^2
= 4A^4/(A^2)^2
= 4A^4/A^4
= 4
kindly approve :))

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