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In Triangle ABC, angle C = 90°, then find the value of sec (A+B)

Ganesh , 6 Years ago
Grade 10
anser 3 Answers
Arun
Dear student
 
sec (A + B) = sec ( 90) = not defined.
 
Hope it helps
 
Regards
Arun
 
In case of any difficulty, please feel free to ask again 
Last Activity: 6 Years ago
Vikas TU
Dear student 
m(angle A) + m(angle B ) + m (angleC ) = 180 °…..sum of the three angles of a triangle is 180°
m(angle A) + m(angle B ) + 90° = 180°
Where angle C is 90 ° (C is right angle given)
m(angle A + angle B ) = 180°- 90° = 90°
Cos( A+ B) = 90°
Cos 90 ° = 0
Sec (A+B) = 1/0 = not defined.
Hope this helps 
Good Luck 
Last Activity: 6 Years ago
sushmitha raj
angleA+angleB+angleC=180o
given,
C=90o
A+B+90=180
A+B=90
Cos(A+B)=cos90
cos(A+B)=0
Sec(A+B)=1/0
Sec(A+B)=not defined
Last Activity: 6 Years ago
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