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`        In Triangle ABC, angle C = 90°, then find the value of sec (A+B) `
3 months ago

```							Dear student sec (A + B) = sec ( 90) = not defined. Hope it helps RegardsArun In case of any difficulty, please feel free to ask again
```
3 months ago
```							Dear student m(angle A) + m(angle B ) + m (angleC ) = 180 °…..sum of the three angles of a triangle is 180°m(angle A) + m(angle B ) + 90° = 180°Where angle C is 90 ° (C is right angle given)m(angle A + angle B ) = 180°- 90° = 90°Cos( A+ B) = 90°Cos 90 ° = 0Sec (A+B) = 1/0 = not defined.Hope this helps Good Luck
```
3 months ago
```							angleA+angleB+angleC=180ogiven,C=90oA+B+90=180A+B=90Cos(A+B)=cos90cos(A+B)=0Sec(A+B)=1/0Sec(A+B)=not defined
```
3 months ago
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