in a triangle ABC if B=3C prove that in(A/2) =(b-c)/2c

Question

Sudhir Kumar · Answer

B = 3C , sin B = sin3C => sinB = sinC(4cos 2 C – 1) Using sin law for sinB and sinC => b = c(4cos 2 C– 1) => cos 2 C = (b+c)/4a A+B+C=180 => A = 180 – 4C =>sin(A/2) = cos2C = 2cos 2 C – 1 => sin(A/2) = (b – c)/2c

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in a triangle ABC if B=3C prove that in(A/2) =(b-c)/2c

in a triangle ABC if B=3C prove that in(A/2) =(b-c)/2c

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