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question mark

if x belongs to [0,90],the number of solutions
of the equation sin7x+sin4x+sinx=0 is

sidharth sunny , 9 Years ago
Grade 11
anser 1 Answers
Riddhish Bhalodia
sin7x + sin4x + sinx = sin4x + 2sin4xcos3x = sin4x(2cos3x + 1) = 0
hence sin4x = 0 and cos3x = -1/2
x = nPI/2 and x = 2nPI Β± 2PI/3
Now find how many are in 0 to 90
Last Activity: 9 Years ago
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