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If tan(theta/2) = 2/3 then sec theta = ?a).13/5 b). 3/13 c). 5/13 d). 12/13
Using formula Tan^(theta/2)=(1-cos□)/(1+cos□)where ^=square and □=theta4/9=(1-cos□)/(1-cos□)By cross multiplication We get 13cos□=5Cos□=5/13Sec□=13/5So (a)
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