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if tan beta = (tan alpha + tan gama)/(1+ tan alpha . tan gama), prove that sin2beta=(sin2alpha + sin2gama)/(1+sin2alpha . sin2gama)

if tan beta = (tan alpha + tan gama)/(1+ tan alpha . tan gama), 
prove that sin2beta=(sin2alpha + sin2gama)/(1+sin2alpha . sin2gama)

Grade:11

1 Answers

Lab Bhattacharjee
121 Points
8 years ago
HINT:  Use      Weierstrass Substitution 
 $$\sin2A=\dfrac{2\tan A}{1+\tan^2A}$$

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