If tanα and tanβ are the roots of the equation X² - px + 6 =0 the sin²(α+β) = ?

Question

Arun · Answer

Dear Vinit tan a + tanb = p tan a * tan b = 6 tan(a+b) = tan a + tan b / (1 – tan a tanb) = p/ 1 – 6 tan(a+b) = p /(1 – 6) sin (a+b) = p / (p 2 + (1 -6) 2 ) hence sin 2 (a+b) = p 2 / (p 2 + 25 )

Deepak Kumar Shringi · Answer

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If tanα and tanβ are the roots of the equation X² - px + 6 =0 the sin²(α+β) = ?

If tanα and tanβ are the roots of the equation
X² - px + 6 =0 the sin²(α+β) = ?

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If tanα and tanβ are the roots of the equation X² - px + 6 =0 the sin²(α+β) = ?

If tanα and tanβ are the roots of the equation X² - px + 6 =0 the sin²(α+β) = ?

2 Answers

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If tanα and tanβ are the roots of the equation
X² - px + 6 =0 the sin²(α+β) = ?