Grade 11Trigonometry
If tanα and tanβ are the roots of the equation X² - px + 6 =0 the sin²(α+β) = ?
If tanα and tanβ are the roots of the equation
X² - px + 6 =0 the sin²(α+β) = ?
2 Answers
Arun
Dear Vinit
tan a + tanb = p
tan a * tan b = 6
tan(a+b) = tan a + tan b / (1 – tan a tanb)
= p/ 1 – 6
tan(a+b) = p /(1 – 6)
sin (a+b) = p / 
(p2 + (1 -6)2)
hence
sin2 (a+b) = p2 / (p2 + 25 )
Deepak Kumar Shringi
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