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If tanα and tanβ are the roots of the equation
X² - px + 6 =0 the sin²(α+β) = ?

vinit arora , 7 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 7 Years ago

 
Dear Vinit
 
tan a + tanb = p
tan a * tan b = 6
 
 
tan(a+b) = tan a + tan b / (1 – tan a tanb)
 
 = p/ 1 – 6
 
tan(a+b) = p /(1 – 6)
 
sin (a+b) = p / \sqrt(p2 + (1 -6)2)
 
hence
 
sin2 (a+b) = p2 / (p2 + 25 )

Deepak Kumar Shringi

Last Activity: 7 Years ago

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