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If tan (A + B) = √3 and tan (A – B) = 1/√3 ,0° B, find A and B.

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one month ago Anand Kumar Pandey
1677 Points
```							Dear Studenttan (A + B) = √3Since √3 = tan60°Now substitute the degree value⇒tan (A + B) = tan 60°(A + B) = 60° ... (i)tan (A– B) = 1/√3Since1/√3 = tan30°Now substitute the degree value⇒tan (A - B) = tan 30°(A - B) = 30° ... equation (ii)Now add the equation (i) and (ii), we get A + B + A - B = 60° + 30°Cancel the terms B2A = 90°A= 45°Now, substitute the value of A in equation (i) to find the value of B 45° + B = 60°B = 60° - 45°B = 15°ThereforeA = 45° and B = 15°Thanks
```
one month ago
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