( * )If sin a + cosec a = 2, then sin^n a + cosec^n a =

Hi,

Just solve the first expression. If you simplify it you will get [SINa-1]^2 = 0
i.e. SIN a = 1.

Now put this value in the second expression.
You will get 2 as answer.

( Dont forget to use : COSEC x= 1/SINx )