If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x0, y

Question

If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x>0, y

noogler · Answer

cosx+cosy-cos(x+y)=3/2 is true if x=y=60 o cos60 o +cos60 o -cos120 o =1/2+1/2-(-1/2)=3/2 SinxSiny=sin60 o sin60 o =3/4 sinx siny=3/4 approve if it is r8 and useful to u..........

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If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x>0, y

If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x>0, y

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If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x>0, y

If cosx+cosy-cos(x+y)=3/2 then find the value of SinxSiny where x>0, y

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