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IF+COS*4/A*3+SIN*4/A=1/A=B SHOW THAT COS*8/A*3+SIN*8/B*3=1/(A+B)*3

IF+COS*4/A*3+SIN*4/A=1/A=B SHOW THAT COS*8/A*3+SIN*8/B*3=1/(A+B)*3

Grade:12th pass

1 Answers

Latika Leekha
askIITians Faculty 165 Points
8 years ago
Hello student,
I think you have missed several terms while typing your question
I am assuming the question is
If cos4x/a + sIn 4x/b = (1/a+b), then we are required to prove that
cos8x/a3 + sIn 8x/b3 = (1/a+b)3
Solution: We know that cos4x = (cos2x)2 = (1 – sin2x)2 = 1 + sin4x – 2sin2x
So, sin4x/b + cos4x/a = 1/(a+b)

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So, cos8x/a3 + sIn 8x/b3 = (1/a+b)3

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