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If A is not in II quadrant B is not in III quadrant and cos A = -1/2 cos B= -1/2. Find the value of 4sin B-3 tan A/tanB + sinA

If A is not in II quadrant B is not in III quadrant and cos A = -1/2 cos B= -1/2. Find the value of 4sin B-3 tan A/tanB + sinA

Grade:11

1 Answers

Arun
25750 Points
4 years ago
Dear student
 
Hence A is in 3rd Quadrant and A = 240 degree
while B is in wnd quadrant and B = 120 degree
 
hence sin B = sin 120 = sqrt (3)/2
tan A = tan 240 = sqrt(3)
tanB = tan 120 = – sqrt (3)
sinA = sin 240 = – sqrt(3)/2
 
now put the values
 
2 sqrt(3) – 3 sqrt(3) / – sqrt(3) – sqrt(3)/2
 
2 /3

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