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If A+B+C=2π then PT cos²B + cos²C - sin²A = 2·cosA·cosB·cosC

If A+B+C=2π then PT cos²B + cos²C - sin²A = 2·cosA·cosB·cosC

Grade:12th pass

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago

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