if a+b+c=180,then prove that- sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]

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Gman Namg · Answer

just take a=b=c=60deg or use the formul of sinc+sind

Gman Namg · Answer

just take a=b=c=60deg or use the formul of sinc+sind

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if a+b+c=180,then prove that- sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]

if a+b+c=180,then prove that-
sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]

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if a+b+c=180,then prove that- sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]

if a+b+c=180,then prove that-sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]

2 Answers

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if a+b+c=180,then prove that-
sin(b+2c)+sin(c+2a)+sin(a+2b)=4sin[(b-c)/2]sin[(c-a)/2]sin[(a-b)/2]