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`        I need help solving both problems. Can someone please solve them? Thanks`
11 months ago

1672 Points
```							Let cosx=ycos2x+cosx= 2y^2+y-1=f(y) suchthat y lies in -1 to 1.Now find f(1), f(-1) and then differentiate f(y) and set it to zero to obtain y=-1/4. Find f(-1/4). Compare these three values and the least one of them is the minimum value.For the first question, write sin^2x and cos^2x in terms of cos2x and sinx-cosx as sin2x/2 and then set 2x=y. Having done this, use the fact that asinx+bcosx lies in -√(a^2+b^2) to √(a^2+b^2).
```
11 months ago
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### Course Features

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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions