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Find the period of the function f(x) = sin(x + 8x + 27x +... + n3x).
f(x)= sin [{n*(n+1)/2}^2x]now, we know that period of f(ax+b) is T/|a|.so, since period of sin is 2pi, the period of f(x) will be 8pi/[n*(n+1)]^2
sigma (1 + 8x + 27 x + …....n^3 x) =x * n^2 (n+1)^2 / 4let this is thence period is 2 * pi/t RegardsArun (askIITians forum expert)
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