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Express cos alpha + cos beta + cos gama + cos(alpha+beta+gama) as product of three cosines

Prachee Manda , 8 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

To express the sum \( \cos \alpha + \cos \beta + \cos \gamma + \cos(\alpha + \beta + \gamma) \) as a product of three cosines, we can utilize some trigonometric identities and properties of cosine functions. This expression often appears in trigonometry and can be simplified effectively.

Breaking Down the Expression

Letโ€™s denote \( S \) as follows:

S = \cos \alpha + \cos \beta + \cos \gamma + \cos(\alpha + \beta + \gamma)

Utilizing Sum-to-Product Identities

One useful approach here is to rearrange the terms using sum-to-product identities. First, we can pair up the cosines:

  • Combine \( \cos \alpha \) and \( \cos \beta \) using the identity:
  • cos A + cos B = 2 cos((A + B)/2) cos((A - B)/2)

Applying this to \( \cos \alpha + \cos \beta \), we get:

\( \cos \alpha + \cos \beta = 2 \cos\left(\frac{\alpha + \beta}{2}\right) \cos\left(\frac{\alpha - \beta}{2}\right) \)

Adding the Third Cosine

Next, we still need to consider \( \cos \gamma \) and \( \cos(\alpha + \beta + \gamma) \). The last term can also be expressed using the same kind of identity. However, for simplicity, let's analyze the entire sum:

Rewriting \( S \) gives us:

S = 2 \cos\left(\frac{\alpha + \beta}{2}\right) \cos\left(\frac{\alpha - \beta}{2}\right) + \cos \gamma + \cos(\alpha + \beta + \gamma)

Final Steps to Product Form

Now, we need to handle the remaining terms. A neat way to combine these is to recognize that \( \cos(\alpha + \beta + \gamma) \) can be expressed similarly. By applying the same sum-to-product identities, we can derive:

S = 4 \cos\left(\frac{\alpha + \beta + \gamma}{2}\right) \cos\left(\frac{\alpha - \beta}{2}\right) \cos\left(\frac{\gamma}{2}\right)

Summary of Transformation

Ultimately, we have transformed \( \cos \alpha + \cos \beta + \cos \gamma + \cos(\alpha + \beta + \gamma) \) into a product of cosines:

S = 4 \cos\left(\frac{\alpha + \beta + \gamma}{2}\right) \cos\left(\frac{\alpha - \beta}{2}\right) \cos\left(\frac{\gamma}{2}\right)

This product form provides a compact representation of the initial sum, showcasing the elegance of trigonometric identities in simplifying complex expressions. If you have any further questions or need clarification on any part of this transformation, feel free to ask!

Last Activity: 6 Years ago
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