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# Cot(a).cot(60+a).cot(60-a)=????????????????????????????

one year ago

Arun
25384 Points

Dear Himanshu

it can be written as 1/ [ tan A tan (60-A) tan (60+A)] =1/ tan 3A

hence = cot 3A

Hope it helps

one year ago
14 Points

Cota.Cot(60+a).Cot(60-a) =cosa.cos(60+a)cos(60-a)/sina.sin(60+a)sin(60-a)=cosa{2cos(60+a).cos(60-a)}/sina{2sin(60+a)sin(60-a)} =cosa.(cos2a+cos120)/sina(cos2a-cos120)=cosa.cos2a+cosa.cos120/sina.cos2a-sina.cos120=2cosa.cos2a-cosa/2sina.cos2a+sina=cosa+cos3a-cosa/sin3a-sina+sina=cos3a/sin3a=cot3a
one year ago
TEJA KRISHNA
42 Points

Dear Himanshu
It can be written as 1/ [ tan A tan (60-A) tan (60+A)] =1/ tan 3A

hence = cot 3A
all the best
hope u understand this
9 months ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions